5x^2=3+8x

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Solution for 5x^2=3+8x equation:



5x^2=3+8x
We move all terms to the left:
5x^2-(3+8x)=0
We add all the numbers together, and all the variables
5x^2-(8x+3)=0
We get rid of parentheses
5x^2-8x-3=0
a = 5; b = -8; c = -3;
Δ = b2-4ac
Δ = -82-4·5·(-3)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{31}}{2*5}=\frac{8-2\sqrt{31}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{31}}{2*5}=\frac{8+2\sqrt{31}}{10} $

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